Oct 31, 2016 6:52 pm
BTW, just looked up how helping on Beginner's Luck tests works, 'cause I never really understood it. For good reason, it seems! Here's the ruling as I understand it now. In brief, think of Beginner's Luck as an obstacle penalty to a stat test which does not factor into anyone's advancement, like artha doesn't.
Concrete example:
Suppose Zachary is going to make a Beginner's Luck -wise test, and Gord is helping. They both have B4 Perception. Let's say the Ob is 2, and Zachary has a +1 Ob disadvantage because, I dunno, he's drunk.
Zachary rolls Beginner's Luck Perception B4+1D=5D against a total Ob of 5. Base Ob doubled, plus disadvantage, is 2*2+1=5.
Zachary's test will be logged as if he rolled 5D against an Ob of 3, base Ob plus disadvantage, 2+1=3. That test would be routine for the stat, so instead it counts as a test toward opening the -wise.
Gord's test will be logged as if he rolled 4D against an Ob of 3 as well. That test would be difficult for the stat, so it counts as a Difficult Perception test.
Concrete example:
Suppose Zachary is going to make a Beginner's Luck -wise test, and Gord is helping. They both have B4 Perception. Let's say the Ob is 2, and Zachary has a +1 Ob disadvantage because, I dunno, he's drunk.
Zachary rolls Beginner's Luck Perception B4+1D=5D against a total Ob of 5. Base Ob doubled, plus disadvantage, is 2*2+1=5.
Zachary's test will be logged as if he rolled 5D against an Ob of 3, base Ob plus disadvantage, 2+1=3. That test would be routine for the stat, so instead it counts as a test toward opening the -wise.
Gord's test will be logged as if he rolled 4D against an Ob of 3 as well. That test would be difficult for the stat, so it counts as a Difficult Perception test.