Ok im confused again.
Quote:
second one was able to sneak in a small scratch of 3 HP worth of damage on Netdraeth.
Rolls
Ant 1 attacks (MAT: 11 + 2 for size, total CTN: 13) - (1d20)
( 13 ) = 13
Netdraeth's DEF: 16 - (1d20)
( 15 ) = 15
Ant 2 attacks (MAT: 11 + 2 for size, total CTN: 13) - (1d20)
( 15 ) = 15
Netdraeths's DEF: 16 - (1d20)
( 1 ) = 1
Ant 3 attacks (MAT: 11 + 2 for size, total CTN: 13) - (1d20)
( 3 ) = 3
Netdraeth's DEF: 16 - (1d20)
( 18 ) = 18
Rerolling Netdraeth,s Coup on 2nd DEF - (1d20)
( 4 ) = 4
it looks like from attack 1, i would take 1 dmg? or non.
attack 2 looks like it missed?
And attack 3 i would take 10?
I thought i had it but im confused again :D